Slugifying German string with Python
I'm working on this project that has some German titles, and a lot of irregularities inside them
(question marks, underscores, etc.)
Because I have to refer the object (in this case product) by some sort of understandable name, I've decided to slugify the title
(basically turn "THIS EXAMPLE!!" to "this-example") While I'm already doing that, I wanted to cleverly switch the "ä,ö,ü,ß" to "ae,oe,ue,ss" accordingly.
I'm pretty sure this might be useful to someone, and it's pretty harmless to share it so...
this gist was born, and the code is:1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28# -*- coding: utf-8 -*- def replace_all(text, dic): for replace_with, replace_what in dic.iteritems(): if type(replace_what) is list: for letter in replace_what: text = text.replace(letter,replace_with) else: text = text.replace(replace_what, replace_with) return text #example input: ssdfSERFS - ^#$%43 GSDG ____ :VKbm sdF öüoäßßEF_____-___ d a s d _e <>DFGDFG???? #example output: ssdfserfs-43-gsdg-vkbm-sdf-oeueoaessssef-d-a-s-d-e-dfgdfg def slugify(string,params = []): import re #unescape html entity signs (e.g. &amp; -> &) & lowercase string import HTMLParser string = HTMLParser.HTMLParser().unescape(string).lower() translation_dic = { 'ae' : ['Ä','ä','&Auml;','&auml;'], 'oe' : ['Ö','ö','&Ouml;','&ouml;'], 'ue' : ['Ü','ü','&Uuml;','&uuml;'], 'ss' : ['ß','&szlig;'], } string = replace_all(string,translation_dic) string = re.sub(r'[^a-zA-Z0-9\_\-\s]','',string) string = re.sub(r'[\s]{2,}',' ',string) string = string.replace(' ','-').replace('_','-').strip(' -') string = re.sub(r'[\-]{2,}','-',string) return stringPosted in TechnologyRunning Django under a Shared Hosting Environment
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